Answer:
2.684 g
Explanation:
Given:
half life (T) = 5.27 years
Initial amount (N₀) = 10 g
time (t) = 21 years
[tex]\boxed{Final\ amount\ (N)=(\frac{1}{2})^{\frac{t}{T}}\cdot N_o}[/tex]
[tex]N=\frac{1}{2} ^{\frac{10}{5.27}} \times10[/tex]
[tex]=2.684\ g[/tex]