Answer:
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Explanation:
Since it is a frictionless ramp, all of the block's POTENTIAL energy (mgh) will be converted to KINETIC energy at the bottom of the ramp
mgh = 1/2 m v^2 Solve for v
v = sqrt (2gh) = sqrt ( 2 * 9.81 * 1.35) = 5.15 m/s
The block slides across the horizontal frictionless ramp (the Q states it does not slow down....so no friction)
At the frictionless uphill ramp the KE will be converted back to PE and the block will stop at the same height it started = 1.35 m
