Question

The sum of three numbers is 81.the second number is twice the first. Given that the third number is 6 more than the second,find the numbers

Answer 1

Answer:

x + y + z = 81

y = 2x

z = y + 6

(1/2)y + y + y + 6 = 81

(5/2)y = 75

y = 75(2/5) = 30

x = 15

z = 36

The numbers are 15, 30, and 36.