To determine the values that make the range of the function, we need to substitute each value from the given domain into the function and calculate the corresponding output.
The given function is h(n) = 6 + 3n/8.
Let's substitute each value from the domain and calculate the outputs:
For n = 0:
h(0) = 6 + 3(0)/8 = 6
For n = 3:
h(3) = 6 + 3(3)/8 = 6 + 9/8 = 6 + 1.125 = 7.125
For n = 12:
h(12) = 6 + 3(12)/8 = 6 + 36/8 = 6 + 4.5 = 10.5
For n = 9:
h(9) = 6 + 3(9)/8 = 6 + 27/8 = 6 + 3.375 = 9.375
For n = -12:
h(-12) = 6 + 3(-12)/8 = 6 - 36/8 = 6 - 4.5 = 1.5
For n = 8:
h(8) = 6 + 3(8)/8 = 6 + 24/8 = 6 + 3 = 9
For n = -3:
h(-3) = 6 + 3(-3)/8 = 6 - 9/8 = 6 - 1.125 = 4.875
For n = 15:
h(15) = 6 + 3(15)/8 = 6 + 45/8 = 6 + 5.625 = 11.625
Comparing these outputs to the given range {-10, 6, 30, 38}, we can see that only the value 6 is included in the range. Therefore, the only value that makes the range of the function is 6.
bye bye! hope this helps!! - sun
