Question

a cyclist is travelling a 5 m/s and brakes for 2 seconds using a force of 150 n. the mass is 90 kg. what is the final velocity

Answer 1

Explanation:

We can calculate the final Velocity of the cyclist using the kinematics Equation,

$v = u + at$

where : v is final Velocity

• u is initial velocity
• a is acceleration
• t is time

We are given, a cyclist is travelling a 5 m/s and brakes for 2 seconds using a force of 150 N, the mass is 90 kg.

Here the initial velocity, u is 5 m/s.

The acceleration (a) of the cyclist can be calculated by using newton's 2nd law of motion

$F = ma$

Plug in the given values

$150 = 90 \times a$

divide both sides by 90

$a = 1.67 m/s^2$

Hence, the acceleration of the cyclist is 1.67 m/s². Now substitute the value of u, a and t in the kinematics equation

$v = 5 + (1.67 \times 2)$

$v = 5 + 3.24$

$\pmb{v = 8.24 m/s}$

Hence, the final velocity of the cyclist is 8.24 m/s