6) A 50 kg block sits on the ground. A force PULLS on the block at an angle of 45o above the horizontal. Find

a) a) the weight of the block.




b) the normal force on the block just as the block lifts off the ground.





c) the pulling force necessary to just barely lift the block off the ground.

Respuesta :

Answer:

Explanation:

The weight of the block is 490 N. The normal force on the block just as it lifts off the ground is also 490 N

To find the weight of the block, we use the formula weight = mass * gravity, where gravity is approximately 9.8 m/s². Therefore, the weight of the 50 kg block is 50 kg * 9.8 m/s² = 490 N.

The normal force on the block just as it lifts off the ground is equal in magnitude and opposite in direction to the weight of the block. So, the normal force will also be 490 N.

The horizontal component can be found using the formula horizontal component = pulling force * cos(angle). Therefore, the pulling force necessary to just barely lift the block off the ground is 490 N / cos(45°) ≈ 692.964 N.

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