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Answer:

75.36 [tex]\Omega[/tex]

Explanation:

The formula to calculate inductive reactance of the coil is given by :

[tex]X_L = 2 \pi f l [/tex]

where:

XL represents inductive reactance of the coil

f represents frequency

l represents inductance of the coil

π is mathematical constant (π = 3.14 )

plug in the the values,

[tex]X_L = 2 \times 3.14 \times 60 \times 0.2 [/tex]

[tex]X_L = 75.36 \: \Omega[/tex]

Hence, the the inductive reactance of the coil is 75.36 [tex]\Omega[/tex]

Final answer:

The inductive reactance of a coil with an inductance of 0.2 H connected to a 60 Hz supply is approximately 75.4 ohms, calculated using the formula XL = 2πfL.

Explanation:

Calculating Inductive Reactance

To calculate the inductive reactance of a coil, we use the formula XL = 2πfL, where XL is the inductive reactance, f is the frequency of the AC supply, and L is the inductance of the coil. Given that the inductance (L) is 0.2 H and the frequency (f) is 60 Hz, we can substitute these values into the formula to find the inductive reactance.

XL = 2 × 3.14159 × 60 Hz × 0.2 H = 75.3982 ohms

Therefore, the inductive reactance of the coil when connected to a 120 V, 60 Hz supply is approximately 75.4 ohms.

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