Question

An athlete competing in the long jump leaves the ground with a speed of 9.14 m/s at an angle of 35 degrees above the horizontal. How long does the athlete stay in the air assuming no significant air resitstance?

Answer 1

Answer:

1.07 s

Explanation:

Given in the y direction:

s = 0 m

u = 9.14 sin 35° = 5.24 m/s

a = -9.8 m/s²

Find: t

s = ut + ½ at²

0 = (5.24) t + ½ (-9.8) t²

0 = 5.24t − 4.9t²

0 = t (5.24 − 4.9t)

t = 0 or 1.07

It takes 1.07 seconds for the athlete to land.