Answer:
C
Step-by-step explanation:
Since the dilatation is centred at the origin , then each of the original coordinates of points D and E are multiplied by the scale factor of [tex]\frac{1}{3}[/tex]
D (0, 9 ) → D' ([tex]\frac{1}{3}[/tex] (0), [tex]\frac{1}{3}[/tex] (9) ) → D' (0, 3 )
E (3, 3 ) → E' ([tex]\frac{1}{3}[/tex] (3), [tex]\frac{1}{3}[/tex] (3) ) → (1, 1 )
to calculate the length of D'E' , use the distance formula
D'E' = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
let (x₁, y₁ ) = D' (0, 3 ) and (x₂, y₂ ) = E' (1, 1 )
substitute these values into the formula for D'E'
D'E' = [tex]\sqrt{(1-0)^2+(1-3)^2}[/tex]
= [tex]\sqrt{1^2+(-2)^2}[/tex]
= [tex]\sqrt{1+4}[/tex]
= [tex]\sqrt{5}[/tex]