Question

a cylindrical jar has diameter 7 cm and contains water to the depth of 5 cm. a sphere of diameter 3 cm is dropped into the jar and sinks to the bottom. the water depth, to the nearest tenth of a centimetre, is now

Answer 1

Answer:

5.4 cm

Step-by-step explanation:

Volume of sphere = additional volume of jar

$\frac{4}{3} \pi r_{sphere}^3=\pi r_{jar}^2h_1$

$4 r_{sphere}^3=3 r_{jar}^2h_1$

$4(\frac{3}{2} )^3=3(\frac{7}{2} )^2h_1$

$h_1=0.4\ cm$

h = 5 + 0.4

  = 5.4 cm