Respuesta :
Answer:
18m²-26+18
so we have 3 in common
so,3[6m²-13+6]
by middle term splitting,
we can write 13 as -9-4 okay
3[6m²-9m-4m+6]
so we make pairs okk
3[(6m²-9m)-(4m-6)]
okay
3[3m(2m-3)-2(2m-3)]
now we have two pairs in common 2m-3
and (3m-2) is without pair
so we will write it as
3[(2m-3)(3m-2)]
so this is answer of any doubt then comment me
Step-by-step explanation:
18m²-26+18
so we have 3 in common
so,3[6m²-13+6]
by middle term splitting,
we can write 13 as -9-4 okay
3[6m²-9m-4m+6]
so we make pairs okk
3[(6m²-9m)-(4m-6)]
okay
3[3m(2m-3)-2(2m-3)]
now we have two pairs in common 2m-3
and (3m-2) is without pair
so we will write it as
3[(2m-3)(3m-2)]
so this is answer of any doubt then comment me