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Answer:
Step-by-step explanation:1. To change the equation to slope-intercept form, we need to solve for y:
2x + 3y = 1,470
3y = -2x + 1,470
y = (-2/3)x + 490
The slope of the equation is -2/3 and the y-intercept is 490.
2. To graph the line using the slope-intercept method, we can start by plotting the y-intercept at (0, 490). Then, we can use the slope of -2/3 to find additional points on the line. For example, we can move down 2 units and to the right 3 units from the y-intercept to get to the point (3, 488). We can continue this process to find more points and then connect them to create a straight line.
3. The equation in function notation is f(x) = (-2/3)x + 490. The graph of the function represents the profit from lunch specials as a function of the number of sandwich lunch specials sold. For any given value of x (number of sandwich lunch specials sold), we can use the equation to find the corresponding value of f(x) (profit from lunch specials).
4. Here is a graph of the function:
Graph of f(x) = (-2/3)x + 490
The x-intercept is (735, 0) and the y-intercept is (0, 490).
it is attached in image below
5. The graphs of the functions for the two months would be similar in shape, but different in location. They would both be straight lines with a slope of -2/3, representing the fact that the profit increases by $2 for each sandwich lunch special sold and by $3 for each wrap lunch special sold. The y-intercept of the second line would be different because the total profit for the next month is higher than the total profit for the previous month.
6. The graph of the third month's profits looks like a horizontal line at a profit of $1,680. This means that the profit is the same regardless of how many sandwich or wrap lunch specials are sold. The equation of the line would be y = 1680, since the y-value is constant for all x-values
1. To change the equation to slope-intercept form, we need - 1
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