Respuesta :

[tex]\bf sin(\theta)=\cfrac{opposite}{hypotenuse} \qquad cos(\theta)=\cfrac{adjacent}{hypotenuse} \quad % tangent tan(\theta)=\cfrac{opposite}{adjacent}\\\\ -------------------------------\\\\ tan(x^o)=\cfrac{11}{r}\cfrac{\leftarrow opp}{\leftarrow adj}\qquad cos(x^o)=\cfrac{r}{s}\cfrac{\leftarrow adj}{\leftarrow hyp}\\\\\\ \boxed{sin(x^o)=\cfrac{11}{s}\cfrac{\leftarrow opp}{\leftarrow hyp}}[/tex]

Answer:

[tex]sin x = \frac{11}{s}[/tex]

Step-by-step explanation:

[tex]Tan x = \frac{11}{r}[/tex]

[tex]Cos x = \frac{r}{s}[/tex]

Property : [tex]\frac{sin \theta}{cos \theta}=Tan \theta[/tex]

So, [tex]\frac{sinx}{cosx}=Tan x[/tex]

Substitute the values

[tex]\frac{sinx}{ \frac{r}{s}}=\frac{11}{r}[/tex]

[tex]sinx =\frac{11}{r} \times \frac{r}{s}[/tex]

[tex]sinx =\frac{11}{s}[/tex]

Hence the value of sin x° is [tex]\frac{11}{s}[/tex]

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