Respuesta :
[tex]\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\quad
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\
tan(x^o)=\cfrac{11}{r}\cfrac{\leftarrow opp}{\leftarrow adj}\qquad cos(x^o)=\cfrac{r}{s}\cfrac{\leftarrow adj}{\leftarrow hyp}\\\\\\ \boxed{sin(x^o)=\cfrac{11}{s}\cfrac{\leftarrow opp}{\leftarrow hyp}}[/tex]
Answer:
[tex]sin x = \frac{11}{s}[/tex]
Step-by-step explanation:
[tex]Tan x = \frac{11}{r}[/tex]
[tex]Cos x = \frac{r}{s}[/tex]
Property : [tex]\frac{sin \theta}{cos \theta}=Tan \theta[/tex]
So, [tex]\frac{sinx}{cosx}=Tan x[/tex]
Substitute the values
[tex]\frac{sinx}{ \frac{r}{s}}=\frac{11}{r}[/tex]
[tex]sinx =\frac{11}{r} \times \frac{r}{s}[/tex]
[tex]sinx =\frac{11}{s}[/tex]
Hence the value of sin x° is [tex]\frac{11}{s}[/tex]