Respuesta :

hr1301
i'm pretty sure its A

Answer:

(A)

Step-by-step explanation:

From the figure, since RT is parallel to QU, therefore ΔSQU is similar to ΔSRT, thus using the basic proportionality theorem, we get

[tex]\frac{SR}{SQ}=\frac{ST}{SU}[/tex]

[tex]\frac{c}{12+c}=\frac{10}{25}[/tex]

[tex]25c=120+10c[/tex]

[tex]15c=120[/tex]

[tex]c=8[/tex]

Also, QU is parallel to PV, therefore from ΔPVS and ΔSRT, we have

[tex]\frac{SR}{SP}=\frac{ST}{SV}[/tex]

[tex]\frac{c}{c+12+d}=\frac{10}{30}[/tex]

[tex]\frac{8}{20+d}=\frac{1}{3}[/tex]

[tex]24=20+d[/tex]

[tex]d=4[/tex]

Now, from ΔSRT and SQU, we have

[tex]\frac{RT}{QU}=\frac{ST}{SU}[/tex]

[tex]b=\frac{10{\times}12.5}{25}[/tex]

[tex]b=5[/tex]

Also, from ΔSQU and SPV,

[tex]\frac{12.5}{a}=\frac{25}{30}[/tex]

[tex]a=15[/tex]

Thus, value of a,b,c and d are 15,5,8 and 4 respectively.

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