Answer:
(A)
Step-by-step explanation:
From the figure, since RT is parallel to QU, therefore ΔSQU is similar to ΔSRT, thus using the basic proportionality theorem, we get
[tex]\frac{SR}{SQ}=\frac{ST}{SU}[/tex]
[tex]\frac{c}{12+c}=\frac{10}{25}[/tex]
[tex]25c=120+10c[/tex]
[tex]15c=120[/tex]
[tex]c=8[/tex]
Also, QU is parallel to PV, therefore from ΔPVS and ΔSRT, we have
[tex]\frac{SR}{SP}=\frac{ST}{SV}[/tex]
[tex]\frac{c}{c+12+d}=\frac{10}{30}[/tex]
[tex]\frac{8}{20+d}=\frac{1}{3}[/tex]
[tex]24=20+d[/tex]
[tex]d=4[/tex]
Now, from ΔSRT and SQU, we have
[tex]\frac{RT}{QU}=\frac{ST}{SU}[/tex]
[tex]b=\frac{10{\times}12.5}{25}[/tex]
[tex]b=5[/tex]
Also, from ΔSQU and SPV,
[tex]\frac{12.5}{a}=\frac{25}{30}[/tex]
[tex]a=15[/tex]
Thus, value of a,b,c and d are 15,5,8 and 4 respectively.