Respuesta :
So I'm guessing the answer is: any x from -6 to 6; any absolute value > 6 is not meaningful in this case because the x-axis represents the ground level, and no y values can be negative (underground). Range: y values from 0 (ground) up to 36 (an upward measure, in some kind of units). Drone flying upward is y = mx+b; choose m > 0 and b > 0 (e.g. m = 0.5, b = 24)--this will intersect the rainbow twice; you can find those points of intersection by setting the y values of line & parabola =, and solving the resulting quadratic equation by using the quadratic formula. x values of intersection are about -3.60 and 3.35.
Based on the docx you showed me, the equation for the parabola is [tex]y = x^2 + 36[/tex] and you want a table of values for a linear equation that intersects the parabola at (5, 6) and (-2, 34).
If you use these two points to create a line we get the equation:
[tex]y - 6 = \frac{34 - 6}{-2 - 5}(x - 5)[/tex] (I just used point slope form)
This can be simplified to:
[tex]y = \frac{40}{-7}x + \frac{242}{7}[/tex]
Now we just need to create a table of points on this line. We already have the points you gave and we can also use the y-intercept: [tex](0, \frac{242}{7})[/tex] and the x-intercept: [tex](\frac{121}{20}, 0)[/tex].
So our table of value can be:
x | y
______|________
-2 | 34
0 | 242 / 7
5 | 6
121/20 | 0
If you use these two points to create a line we get the equation:
[tex]y - 6 = \frac{34 - 6}{-2 - 5}(x - 5)[/tex] (I just used point slope form)
This can be simplified to:
[tex]y = \frac{40}{-7}x + \frac{242}{7}[/tex]
Now we just need to create a table of points on this line. We already have the points you gave and we can also use the y-intercept: [tex](0, \frac{242}{7})[/tex] and the x-intercept: [tex](\frac{121}{20}, 0)[/tex].
So our table of value can be:
x | y
______|________
-2 | 34
0 | 242 / 7
5 | 6
121/20 | 0