Respuesta :
[tex]2x^2 + 6x - 9 = 3x^2 - 11x - 7\\
x^2-17x+2=0\\
a=1\\
b=-17\\
c=2[/tex]
2x^2 + 6x - 9 = 3x^2 - 11x - 7
Subtract 2x^2 from both sides
6x - 9 = x^2 - 11x - 7
Substract 6x from both sides
-9 = x^2 - 17x - 7
Add 9 to both sides
0 = x^2 - 17x + 2
a = 1
b = -17
c = 2
Subtract 2x^2 from both sides
6x - 9 = x^2 - 11x - 7
Substract 6x from both sides
-9 = x^2 - 17x - 7
Add 9 to both sides
0 = x^2 - 17x + 2
a = 1
b = -17
c = 2