Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16).

What is the y-value of P'?

Respuesta :

The y-value is the one on the right. Therefore, the y-value of P is 6. Following the rule, the y-value of P' is 6-16= -10.
P(–2, 6)

translated according to the rule (x, y) → (x – 2, y – 16)

P' will be:
P'(–4, -10)

So y value will be - 10

hope it helps
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