Question

If two sides of a triangle are 12 and 17, and the included angle is 60, what is the area of the triangle

Answer 1

The area of a triangle is half the product of two sides times the sine of the included angle.

$A= \frac{1}{2}*12*17*sin(60^o) =102* \frac{ \sqrt{3} }{2}=51 \sqrt{3} \approx 88.33 \ units^2$