If the line is parallel, then it has the same slope as the reference line, in this case: m=-2/3.
It must pass through the point (4, -5)
Point-slope form is: y-y1=m(x-x1) where m=slope, (x1,y1) is a point on the line so:
y--5=(-2/3)(x-4)
y+5=(-2/3)(x-4)
The answer is D