Question

1. In triangle ∆PQR, C is the centroid.


a. If CY = 10, find PC and PY

b. If QC = 10, find ZC and ZQ


If PX = 20, find PQ

Answer 1

Since C is the centroid, therefore:

Segments PZ = ZR;  RY = YQ; QX = XP

A.
If CY = 10, then

PC = 2*CY = 20
PY = PC + CY = 20 + 10 = 30
Answer:      PC = 20      PY = 30

B.
If QC = 10, then

ZC = QC/2 = 5
ZQ = ZC + QC = 5 + 10 = 15
Answer:      ZC = 5        ZQ = 15

C.
If PX = 20
Because the median RX bisects side PQ, therefore PX = QX = 20
PQ = PX + QX = 40
Answer:      PQ = 40