Respuesta :

Amplitude: 3; period: pi/2; midline: y = 2

Answer:

The amplitude of the function is 3, period of the function is [tex]\frac{\pi}{2}[/tex] and midline of the function is 2.

Step-by-step explanation:

The given function is

[tex]f(x)=3\cos(4x-\pi)+2[/tex]               .... (1)

The standard form of a Cosine function is

[tex]g(x)=a\cos(bx+c)+d[/tex]               ... (2)

where, a is amplitude, period is [tex]\frac{2\pi}{b}[/tex] and d is midline.

From (1) and (2), we get

[tex]a=3,b=4,d=2[/tex]

The amplitude of the function is

[tex]a=3[/tex]

The period of the function is

[tex]\frac{2\pi}{b}=\frac{2\pi}{4}=\frac{\pi}{2}[/tex]

The midline of the function is

[tex]d=2[/tex]

Therefore the amplitude of the function is 3, period of the function is [tex]\frac{\pi}{2}[/tex] and midline of the function is 2.

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