Respuesta :
the equation given has a slope of 2/3. A parallel line will have the same slope.
y = mx + b
slope(m) = 2/3
(1,-2)...x = 1 and y = -2
sub and find b, the y int
-2 = 2/3(1) + b
-2 = 2/3 + b
-2 - 2/3 = b
-6/3 - 2/3 = b
- 8/3 = b
equation is : y = 2/3x - 8/3...but we need it in standard form
y = 2/3x - 8/3
-2/3x + y = -8/3...multiply by -3
2x - 3y = 8 <== standard form
y = mx + b
slope(m) = 2/3
(1,-2)...x = 1 and y = -2
sub and find b, the y int
-2 = 2/3(1) + b
-2 = 2/3 + b
-2 - 2/3 = b
-6/3 - 2/3 = b
- 8/3 = b
equation is : y = 2/3x - 8/3...but we need it in standard form
y = 2/3x - 8/3
-2/3x + y = -8/3...multiply by -3
2x - 3y = 8 <== standard form