Respuesta :
Answer: 15 % ( approx)
Step-by-step explanation:
Let S represents the event that the car is SUV.
And W is the event that the car is white.
Then According to the question,
23% of the cars manufactured last year were SUVs,
Thus, the probability of SUV Car,
[tex]P(S)= \frac{23}{100} =0.23[/tex]
Similarly Probability that the car is white,
[tex]P(W)= \frac{13}{100} =0.13[/tex]
And, the probability that cars manufactured were white SUVs,
[tex]P(S\cap W)= \frac{2}{100} =0.02[/tex]
Thus, the probability that a car is an SUV, given that it is white,
[tex]P(\frac{S}{W} )= \frac{P(S\cap W)}{P(W)} = \frac{0.02}{0.13}[/tex] = 0.15384615384= 15.384615384 % ≈ 15 %
Therefore, Option B is correct.