Question

use the quadratic formula to solve 3x^2-x+6=0

Answer 1

x = ( -b +/- sqrt( b^2 - 4ac ) / 2a,

a = 3, b = -1, c= 6 in this particular case:

x = (1 +/- sqrt( 1 -72 ) ) / 6,

sqrt(-71) is imaginary. So no real solutions. If you haven't covered complex numbers, the answer is no solutions.