Question

What is the concentration of hydroxide ions in a solution with a pH of 5.24?
5.75 × 10-6
1.74 × 10-9
1.55 × 10-7
4.54 × 10-4

Answer 1

pOH=-lg[OH⁻]

pOH=14-pH

-lg[OH⁻]=14-pH

[OH⁻]=10^(pH-14)

[OH⁻]=10^(5.24-14)=1.7378×10⁻⁹ ≈1.74×10⁻⁹ mol/L

Answer 2

Answer:

The concentration of hydroxide ions in a solution with a pH of 5.24 is $1.74\times 10^{-9} M$.

Explanation:

The pH of the solution is defined as negative logarithm of $H^+$ ions in solution.

$pH=-\log[H^+]$

The pH of the solution = 5.24

Sum of pH and pOH is equal to 14.

$pH+pOH=14$

$pOH=14-pH=14-5.24=8.76$

$pOH=-\log[OH^-]$

$8,76=\log[OH^-]$

$[OH^-]=1.7378\times 10^{-9}\approx=1.74\times 10^{-9} M$

The concentration of hydroxide ions in a solution with a pH of 5.24 is $1.74\times 10^{-9} M$.