Question

Which answer does NOT correctly describe the graph of y = 5x + 12?

The answer choices are 1. The Line Has A Constant Rate Of Change 2. The Graph Contains The Point (5, 12) 3. The Line Crosses The y-axis 12 Units Above The Origin 4. The Slope Of The Line Can be written as 5/1

Answer 1

Answer

2. The Graph Contains The Point (5, 12)

Explanation

Remember that in a linear function of the form $y=mx+b$, $m$ is the slope/rate of change of the line and $b$ is the y-intercept.

From our equation we can infer that $b=12$, so the y-intercept of our graph is 12 units above the origin on the point (0, 12). Therefore, choice 2 correctly describe the graph of y = 5x + 12

We can also infer that $m=5$, so the slope of our line is 5, which is constant, so our line has a constant rate of change. Also, since every integer can be written as a fraction with denominator 1, we can write our slope as $m=\frac{5}{1}$. Therefore, choices 1 and 2 correctly describe the graph of y = 5x + 12.

Now, remember that any point on the plane has coordinates $(x,y)$, so, to check if a point is on a line, we just need to replace the $x$ and $y$ values in the line equation and check if the equation holds. Our point is (5, 12), so x = 5 and y = 12. Lets replace the values in our line:

$y=5x+12$

$12=5(5)+12$

$12=25+12$

$12\neq 37$

Since the equation equation doesn't hold (12 is not equal 37), we can conclude that the graph doesn't contain the point (5, 12). Therefore, choice 2 does NOT correctly describe the graph y = 5x +12.

Answer 2

Answer:

The graph contains the point (5,12)

I got it right on t t m