Respuesta :
Answer: A=2, B=2 and C=4
Explanation: Oxygen is the element with atomic number 8 and thus contains 8 electrons which are filled in order of increasing energy levels.
[tex]O:8:1s^22s^22p^4[/tex]
The valence electrons are electrons which are present in the valence shell i.e. the last shell. Thus the valence electrons of Oxygen are in shell 2 in which s orbital contains two electrons and the p orbital contains 4 electrons.
Thus A= 2, B=2 and C=4.
Answer:
The correct number of valance electrons in the electronic configuration of Oxygen is:
A=2, B=2, and C=4
Explanation:
The atomic number of oxygen is 8
The electronic configuration will be,
[tex]\rm O_8\rightarrow1s_2,2s_2,2p_4[/tex]
The electrons present in the outermost shell is called valence electrons.
Hence, in the second shell, the s-orbital contains 2 electrons and the p-orbital contains 4 electrons.
If all the electrons in the outermost shell are removed the first shell becomes a valance shell where 2 electrons are present in the s-orbital.
Therefore correct valence electron configuration is 2,2,4.
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