Let h = depth of the rectangular tank.
Its volume is
V = (0.450 m)*(0.900 m)*(h m)
= 0.405h m³
The density of gasoline is about 0.77 kg/L = 719.7 kg/m³.
Because the mass of gasoline is given as 36.0 kg, its volume is
V = (36.0 kg)/(719.7 kg/m³)
= 0.05 m³
Therefore,
0.405h = 0.05
h = 0.1235 m
The capacity of the tank in gallons is
(36 kg)/(0.77 kg/L) = 46.75 L
Because 1 L = 0.264 gal, the capacity is
(46.75 L)/(1/0.264 L/gal) = 177.1 gal.
A typical passenger can hold between 12 and 17 gallons, so this tank is too large.
Answer:
The depth is 0.1235 m.
The volume is 0.05 m³.
The tank is too large for a passenger car.
