Respuesta :
Refer to the figure shown below which illustrates the problem.
Low tides occur at a depth of 2.5 m at 12:00 am and 12:30 pm, separated by a period of T = 12.5 hours.
Likewise, high tides occur at a depth of 5.5 m at 6:15 am and 6:45 pm, separated by a period of T = 12.5 hours.
Use a time coordinate of t hours.
The amplitude is (1/2)*(5.5 - 2.5) = 1.5 m.
Use x(t) to denote depth at time t.
Because x(0)=2.5 and x(T/2) = 5.5,, use the periodic function
[tex]x(t)=-1.5\,cos( \frac{2 \pi t}{12.5} )+4[/tex]
Verify the model.
x(0) = -1.5 + 4 = 2.5
x(6.25) = 1.5 + 4 = 5.5
x(12.5) = -1.5 + 4 = 2.5
A computer plot for x(t) is shown in the accompanying figure.
Low tides occur at a depth of 2.5 m at 12:00 am and 12:30 pm, separated by a period of T = 12.5 hours.
Likewise, high tides occur at a depth of 5.5 m at 6:15 am and 6:45 pm, separated by a period of T = 12.5 hours.
Use a time coordinate of t hours.
The amplitude is (1/2)*(5.5 - 2.5) = 1.5 m.
Use x(t) to denote depth at time t.
Because x(0)=2.5 and x(T/2) = 5.5,, use the periodic function
[tex]x(t)=-1.5\,cos( \frac{2 \pi t}{12.5} )+4[/tex]
Verify the model.
x(0) = -1.5 + 4 = 2.5
x(6.25) = 1.5 + 4 = 5.5
x(12.5) = -1.5 + 4 = 2.5
A computer plot for x(t) is shown in the accompanying figure.


Answer: A cosine function would be a simpler model for the situation.
The minimum depth (low tide) occurs at
t = 0. A reflection of the cosine curve also has a minimum at t = 0.
A sine model would require a phase shift, while a cosine model does not.
Step-by-step explanation:
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