so hmm notice, 12, 23, 34, 45
is simply adding 11 units to get the next value, thus, our "common difference" is 11 then, and our first number is 12
[tex]\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=11\\
a_1=12
\end{cases}\\\\\\ a_n=12+(n-1)11\\\\
-------------------------------\\\\
\textit{on the 15th day n = 15}\qquad a_{15}=12+(15-1)11[/tex]