Respuesta :
The number of hours needed for the company to break even happens when
[tex]R(h)=C(h)[/tex]
[tex]20+45h= 5h^{2}-30 [/tex], rearranging to make the equation 'zero' on LHS
[tex]0= 5h^{2}-30-20-45h [/tex]
[tex]0= 5h^{2}-45h-50 [/tex], divide each term by 5
[tex]0= h^{2}-9h-10 [/tex], factorise
[tex]0=(h+1)(h-10)[/tex], equate each factor to zero
[tex]h=-1 [/tex] and [tex]h=10[/tex]
We choose the positive value of [tex]h[/tex]
Hence, the number of hours needed to break even is [tex]h=10[/tex]
[tex]R(h)=C(h)[/tex]
[tex]20+45h= 5h^{2}-30 [/tex], rearranging to make the equation 'zero' on LHS
[tex]0= 5h^{2}-30-20-45h [/tex]
[tex]0= 5h^{2}-45h-50 [/tex], divide each term by 5
[tex]0= h^{2}-9h-10 [/tex], factorise
[tex]0=(h+1)(h-10)[/tex], equate each factor to zero
[tex]h=-1 [/tex] and [tex]h=10[/tex]
We choose the positive value of [tex]h[/tex]
Hence, the number of hours needed to break even is [tex]h=10[/tex]
Answer:
The number of hours needed for the company to break even happens when
, rearranging to make the equation 'zero' on LHS
, divide each term by 5
, factorise
, equate each factor to zero
and
We choose the positive value of
Hence, the number of hours needed to break even is
Step-by-step explanation: