check the picture below, y = 0 when that happens
[tex]\bf -16t^2+120=0\implies 120=16t^2\implies \cfrac{120}{16}=t^2\implies \cfrac{15}{2}=t^2
\\\\\\
\sqrt{\cfrac{15}{2}}=t[/tex]
bear in mind the square root would give us a +/- roots, however, since this is seconds, a negative unit would be unfeasible, thus we only used the positive root from it.