Araiscool1 Araiscool1

19-07-2017
Mathematics

contestada

I won tickets to a trip for four to the Super Bowl. I have eight friends but I can only bring three of them. In how many ways can I form my Super Bowl party?

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konrad509 konrad509

19-07-2017

[tex]8C3=\dfrac{8!}{3!5!}=\dfrac{6\cdot7\cdot8}{2\cdot3}=56[/tex]

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bryant2706002386 bryant2706002386

18-11-2020

Answer:

56

Step-by-step explanation:

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