Question

When a crew rows with the​ current, it travels 18 miles in 3 hours. Against the​ current, the crew rows 6 miles in 3 hours. Let x=the ​crew's rowing rate in still water and let y = the rate of the current. Find the rate of rowing in still water and the rate of the current.

Answer 1

d=vt, distance equal velocity times time.

3(x+y)=18 and 3(x-y)=6  divide both equations by three

x+y=6 and x-y=2  now add the two equations together...

x+x+y-y=6+2

2x=8  divide both sides by 2

x=4 mph, and since x+y=6

4+y=6

y=2 mph

So the speed of the boat in still water is 4mph and the speed of the current is 2mph.

Answer 2

The speed of the boat in still water is 4mph and the speed of the current is 2mph.

Using the distance formula expressed as:

Distance = speed * time

d = st

Let x be the ​crew's rowing rate in still water and;

let y be the rate of the current

If a crew rows with the​ current and it travels 18 miles in 3 hours, the

3(x+y)=18

If they row against the​ current, the crew rows 6 miles in 3 hours then;

3(x-y)=6  

The equations becomes

x + y = 6

x - y = 2

Add both equations

2x = 6 + 2

2x = 8

x = 4

Recall that x + y = 6

4 + y = 6

y = 2

Hence the speed of the boat in still water is 4mph and the speed of the current is 2mph.

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