Question

  If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s, what is the acceleration of the object?
    
  A. 13.58 m/s
  B. 2.75 m/s
  C. 33 m/s
  D. 5.42 m/s
 

Answer 1

$Given:\\v_0=65 \frac{m}{s} \\v_1=98\frac{m}{s}\\t=12s\\\\Find:\\a=?\\\\Solution:\\\\a= \frac{\Delta v}{t} \\\\\Delta v=v_1-v_0\\\\a= \frac{v_1-v_0}{t} \\\\a= \frac{98\frac{m}{s}-65\frac{m}{s}}{12s} =2,75 \frac{m}{s^2} \\\\Answer\;\;B$

Answer 2

The answer is 2.75 m/s. you can get it by using a formula (v-u)/t.