Question

You replace a 200 W lamp with a more efficient 55 W LED lamp. If you leave your lights on 24 hours a day, how much energy are you saving each day by replacing this bulb?
A.21,225,000 J
B.17,280,000 J
C.4,752,000 J
D.12,528,000 J

Answer 1

$P_1=200W\\P_2=55W\\t=24h=86400s\\\\Find:\\\Delta W=?\\\\Solution:\\\\\Delta W=W_1-W_2\\\\W=Pt\\\\\Delta W=P_1t-P_2t=t(P_1-P_2)\\\\\Delta W=86400s(200W-55W)=12,528,000J\\\\Answer\;\;D$

Answer 2

The amount of energy will be 12,528,000 J.

What is energy?

Energy represents the ability to do tasks. This could exist in several forms, including potential, kinetic, thermal, electrical, chemical, radioactive, and others.

Given data:

$P_{1} = 200 W\\P_{2} = 55W$

Calculation of energy

The energy can be calculated by using the formula:

ΔW = $W_{1} - W_{2}$

It is known that, w = pt

where, w is energy and p is power.

ΔW =

$= P_{1}t - P_{2}t = t(P_{1}- P_{2}) \\= 86400 (200 - 55) \\= 12528000 J$

Therefore, the amount of energy will be 12,528,000 J.

To know more about energy.

https://brainly.com/question/1932868

#SPJ2