Question

A large balloon is initially filled to a volume of 25.0 l at 353 k and a pressure of 2575 mm hg. what volume of gas will the balloon contain at 1.35 atm and 253 k? 6) _______
a.45.0 l
b.11.4 l
c.87.5 l
d.22.2 l
e.58.6 l

Answer 1

Use the combined law of gases:

PV / T = constant => P1 * V1 / T1 = P2 * V2 / T2

=> V2 = (P1 * V1 * T2) / (T1 * P2)

=> V2 = (2575 mmHg * 1 atm / 760 mmHg * 25.0 l * 253 K ) / (353K * 1.35 atm)

V2 = 44. 97 l ≈ 45.0 l

Answer: option a. 45.0 l

Answer 2

The final volume of the balloon at the given temperature is 45 l.

General gas law

The volume of the balloon is determined by applying general gas law as shown below;

V₂ = (V₁P₁T₂)/(T₁P₂)

Where;

P₁ = 25 L

V₁ = 2575 mmHg

T₁ = 353 K

P₂ = 1.35 atm = 1206 mmHg

T₂ = 253 K

V₂ = ?

The final volume of the balloon at the given temperature is calculated as follows;

V₂ = (25 x 253 x 2575)/(353 x 1026)

V₂ = 45 l

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