Question

Consider a political discussion group consisting of 4

​Democrats, 6

​Republicans, and 6

Independents. Suppose that two group members are randomly​ selected, in​ succession, to attend a political convention. Find the probability of selecting a

Democrat

and then a

Republican
.

Answer 1

We know that there are 4+6+6=16 members including 4 Democrats, 6 Republicans, and 6 Independents .
P(selecting a Democrat):
4/16=2/8=1/4
P(selecting a Republican):
6/16=3/8
Next, this problem is known as compound events or probability. To find the answer, take the two probabilities that we found above, and Multiply oth of them together.
P(selecting a Democrat then a Republican):
1/4*3/8=3/32. As a result, the probability of selecting a Democrat and then selecting a Republican is 3/32. Hope it help!

Answer 2

Answer: 0.1

Step-by-step explanation:

Given : The number of Democrats : 4

The number of Republicans : 6

The total number of group members =$4+6+6=16$

The probability that the first member selected is Democrat :-

$\dfrac{4}{16}=\dfrac{1}{4}$

Now, the total number of group members left = 15

The probability that the second member selected is Republican  :-

$\dfrac{6}{15}=\dfrac{2}{5}$

Now, the required probability will be :_

$\dfrac{1}{4}\times\dfrac{2}{5}=\dfrac{1}{10}=0.1$