Respuesta :

I hope this helped. I did everything in one step but u can definitely show more work
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Answer:

[tex]\frac{y(y+2)}{y+1}[/tex]

Explanation:

We have been given the expression [tex]\frac{y^{2}} {y-3} *\frac{{y^{2}-y-6}} {y^2+y}[/tex]

We will factorise the expression

[tex]y^2-y-6=(y+2)(y-3)[/tex] substituting this value in the given expression we will get

[tex]\frac{y^2}{y-3}* \frac{(y+2)(y-3)}{y(y+1)}[/tex]

we can rewrite it as

[tex]\frac{y^2(y+2)(y-3)}{y(y-3)(y+1)}[/tex]

Cancel out the common factor which is y and (y-3) we wil get

[tex]\frac{y(y+2)}{y+1}[/tex]  

Therefore, [tex]\frac{y(y+2)}{y+1}[/tex]