Respuesta :
I hope this helped. I did everything in one step but u can definitely show more work
Answer:
[tex]\frac{y(y+2)}{y+1}[/tex]
Explanation:
We have been given the expression [tex]\frac{y^{2}} {y-3} *\frac{{y^{2}-y-6}} {y^2+y}[/tex]
We will factorise the expression
[tex]y^2-y-6=(y+2)(y-3)[/tex] substituting this value in the given expression we will get
[tex]\frac{y^2}{y-3}* \frac{(y+2)(y-3)}{y(y+1)}[/tex]
we can rewrite it as
[tex]\frac{y^2(y+2)(y-3)}{y(y-3)(y+1)}[/tex]
Cancel out the common factor which is y and (y-3) we wil get
[tex]\frac{y(y+2)}{y+1}[/tex]
Therefore, [tex]\frac{y(y+2)}{y+1}[/tex]