Question

What type of triangle has side lengths 2, √11, and √15? please leave details as to how you got to your conclusion im confused

Answer 1

Let "a", "b" and "с"  be sides of the triangle ("с" is the longest side). The triangle will be:
right if       a² + b² = c²
аcute if     a² + b² > c²    
obtuse if   a² + b² < c²    

We have a=2, b=√11 and c=√15

2² + (√11)² = 4 + 11 = 15
and
(√15)² = 15

15 = 15   ⇒  right triangle.

Hope this helps.

Answer 2

Answer:

right triangle.

Step-by-step explanation:

The given length of the three sides of the triangle are

$2,\sqrt{11},\sqrt{15}$

We will now check whether these three numbers are Pythagorean triple or not. If it is a Pythagorean triple then the triangle will be a right triangle.

Pythagorean triple:- If the sum of square of any two sides is equal to the square of the third side then the lengths are Pythagorean triple and the triangle is a right triangle.

Now, we do the below operation:

$2^2+(\sqrt{11})^2\\\\=4+11\\\\=15$

Now, let us square the third side

$(\sqrt{15})^2\\\\=15$

Since, we got both values equal. Hence, the length of sides are Pythagorean triple.

And therefore, the triangle is right triangle.