Respuesta :

The y intercept is -2, but I don't remember how to find the vertex sorry

Answer:

the vertex is (4, -2) and y-intercept is -6

Step-by-step explanation:

we need to identify the vertex and the y-intercept of the given function

[tex]y=-0.25(x-4)^{2}-2[/tex]

Since, In general the equation of parabola

[tex]y=a(x-h)^{2}+k[/tex] where (h,k) is vertex of parabola

Compare [tex]y=-0.25(x-4)^{2}-2[/tex] with [tex]y=a(x-h)^{2}+k[/tex]

so, the vertex is (4, -2)

and y-intercept is find by put x=0 in equation

[tex]y=-0.25(0-4)^{2}-2[/tex]

[tex]y=-0.25(4)^{2}-2[/tex]

[tex]y=-0.25(16)-2[/tex]

[tex]y=-4-2[/tex]

[tex]y= -6[/tex]

Therefore, the vertex is (4, -2) and y-intercept is -6

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