Respuesta :
The y intercept is -2, but I don't remember how to find the vertex sorry
Answer:
the vertex is (4, -2) and y-intercept is -6
Step-by-step explanation:
we need to identify the vertex and the y-intercept of the given function
[tex]y=-0.25(x-4)^{2}-2[/tex]
Since, In general the equation of parabola
[tex]y=a(x-h)^{2}+k[/tex] where (h,k) is vertex of parabola
Compare [tex]y=-0.25(x-4)^{2}-2[/tex] with [tex]y=a(x-h)^{2}+k[/tex]
so, the vertex is (4, -2)
and y-intercept is find by put x=0 in equation
[tex]y=-0.25(0-4)^{2}-2[/tex]
[tex]y=-0.25(4)^{2}-2[/tex]
[tex]y=-0.25(16)-2[/tex]
[tex]y=-4-2[/tex]
[tex]y= -6[/tex]
Therefore, the vertex is (4, -2) and y-intercept is -6