Question

Find the first six terms of the sequence. a1 = 4, an = 2 • an-1 A. 4, 8, 10, 12, 14, 16 B. 0, 2, 8, 10, 12, 14 C. 4, 8, 16, 32, 64, 128 D. 8, 16, 32, 64, 128, 256

Answer 1

The sequence is the following:

$a_1=4$
$a_n=2*a_n_-_1$

the second description means that each term, is 2 times its previous term

so
$a_1=4$

$a_2=2*a_1=2*4=8$

$a_3=2*a_2=2*8=16$

$a_4=2*a_3=2*16=32$

$a_5=2*a_4=2*32=64$

$a_6=2*a_5=2*64=128$


Answer: C) 4, 8, 16, 32, 64, 128

Answer 2

Answer:

c

Step-by-step explanation: