Question

What is the equation of the line that passes through (4, -1) and (-2, 3)?

Answer 1

y=mx+b

m=slope, b=y-intercept 

m=(y2-y1)/(x2-x1), b=value of y when x=0

m=(3--1)/(-2-4)

m=4/-6

m=-2/3, now we have:

y=-2x/3+b, we can solve for b using any point, I'll use (4,-1)

-1=-2(4)/3+b

-1=-8/3+b

-3/3+8/3=b

5/3=b so

y=-2x/3+5/3

Answer 2

y= 3x+2... i believe?