Question

in how many ways can a judge award first, second, and third place in a contest with 10 entries

Answer 1

Since order is important, this is a problem solved by:

n!/(n-k)!, where n=total choices available, k=number of choices made.

10!/(10-3)!

10!/7!

720

Answer 2

720. just multiply 10 9 and 8 because  first, second, and third, that is means three and that's how many numbers you multiply from 10,so it equals 720.

hope this helps

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