Question

Tyson throws a shot put ball weighing 7.26 kg. At a height of 2.1 m above the ground, the mechanical energy of the ball is 172.1 J.


What is the velocity of the ball at the given point?


____ m

Answer 1

Answer:

2.5 m/s

Explanation:

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Answer 2

Answer:

Velocity, v = 2.50 m/s

Explanation:

Given that,

Mass of the ball, m = 7.26 kg

Height above the ground, h = 2.1 m

Mechanical energy of the ball, T = 172.1 J

To find,

The velocity of the ball at the given point.

Solution,

The sum of potential energy and the kinetic energy is called the mechanical energy of an object. It is given by :

$T=K+P$

K is the kinetic energy

P is the potential energy

$T=\dfrac{1}{2}mv^2+mgh$

On rearranging the above equation,

$v^2=\dfrac{2(T-mgh)}{m}$

$v^2=\dfrac{2(172.1-7.26\times 9.8\times 2.1)}{7.26}$

v = 2.50 meters

Therefore, the velocity of the ball at the given point is 2.50 m/s.