Question

I won tickets to a trip for four to the Super Bowl. I have eight friends but I can only bring three of them. In how many ways can I form my Super Bowl party?

Answer 1

The question is how many ways can we choose 3 from 8. We can use the formula $\frac{n!}{(n-r)!r!}$ where $n$ is 8 and $r$ is 3

$\frac{8!}{(8-5)!5!} = \frac{8!}{3!5!} = 56$ ways of choosing three friends from eight total friends

Answer 2

Rip the 4 tickets in half lol