Respuesta :
Any arithmetic sequence can be expressed as:
a(n)=a+d(n-1), a=initial term, d=common difference, n=term number
In this case a=5, and d=-2 so
a(n)=5-2(n-1) which can be simplified...
a(n)=5-2n+2
a(n)=7-2n
The domain is restricted to integers from 1 to +oo.
a(n)=a+d(n-1), a=initial term, d=common difference, n=term number
In this case a=5, and d=-2 so
a(n)=5-2(n-1) which can be simplified...
a(n)=5-2n+2
a(n)=7-2n
The domain is restricted to integers from 1 to +oo.
Answer:
- [tex]a_n=7-2n[/tex]
- All positive integers greater than 1 will be its domain.
Step-by-step explanation:
The explicit equation for an arithmetic sequence is,
[tex]a_n=a_1+(n-1)d[/tex]
Where,
[tex]a_n[/tex] = nth term in the arithmetic sequence,
[tex]a_1[/tex] = 1st term in the arithmetic sequence,
d = common difference.
Here, the first term of 5 and a second term of 3. So the common difference is -2.
Putting the values,
[tex]a_n=5+(n-1)(-2)=5+2-2n[/tex]
i.e [tex]a_n=7-2n[/tex]
As n neither be negative nor fraction, because it is the number of term, so all positive integers greater than 1 will be its domain.