Question

Given a mean of 8 and a standard deviation of 0.7, what is the z-score of the value 9 rounded to the nearest tenth?

Answer 1

[tex]\mu[\tex]=8
[tex]\sigma[\tex]=0.7
x=9

Z=(x-[tex]\mu[\tex])/[tex]\sigma[\tex]
=(9-8)/0.7
=1.43
=1.4 [to the nearest tenth]

Answer 2

Answer: The z-score of the value 9 rounded to the nearest tenth = 1.4

Step-by-step explanation:

Given: Mean $\mu=8$

Standard deviation $\sigma=0.7$

The given random value x= 9

Now, the formula to calculate the z score is given by:-

$z=\dfrac{x-\mu}{\sigma}\\\\\Rightarrow\ z=\dfrac{9-8}{0.7}\\\\\Rightarrow\ z=1.42857142857\approx1.4$

Hence, the z-score of the value 9 rounded to the nearest tenth = 1.4