Question

Choose the correct simplification of (2xy7)2(y4)3.

Answer 1

2^2  = 4   
answer starts with 4
(xy7)^2 = x^2 y(7*2) = x^2y^14
(y^4)^3  = y^(4*3) = y^12

answer is 4x^2 y^14*y^12
                                 =         4x^2 y^(12+14)
                                = 4x^2y^26

D

Answer 2

Answer:

The given expression $\left(2xy^7\right)^2\left(y^4\right)^3$ is simplified to $4x^2y^{26}$

Step-by-step explanation:

Given : Expression  $\left(2xy^7\right)^2\left(y^4\right)^3$

We have to write the correct simplification for the given expression $\left(2xy^7\right)^2\left(y^4\right)^3$

Consider the given expression $\left(2xy^7\right)^2\left(y^4\right)^3$

Apply exponent rule, $\left(a\cdot \:b\right)^n=a^nb^n$

We have,

$=2^2x^2\left(y^7\right)^2$

Simplify, we have,

$=2^2x^2y^{14}$

Apply exponent rule, $\left(a^b\right)^c=a^{bc}$

Simplify, we have,

$=y^{4\cdot \:3}=y^{12}$

Thus, The expression becomes, $=2^2x^2y^{14}y^{12}$

Apply exponent rule, $\:a^b\cdot \:a^c=a^{b+c}$

$y^{14}y^{12}=\:y^{14+12}=\:y^{26}$

Simplify, we have,

$=4x^2y^{26}$

Thus, The given expression $\left(2xy^7\right)^2\left(y^4\right)^3$ is simplified to $4x^2y^{26}$