Question

Solve log_x(1/32)=-5

Answer 1

remember

$log_a(b)=c$ translates to $a^c=b$

so
$log_x(\frac{1}{32})=-5$ translates to $x^{-5}=\frac{1}{32}$
remember, if a^b=c^b when b=b, then a=c
and x^-m=1/(x^m)

hmm
$x^{-5}=\frac{1}{32}$
$\frac{1}{x^5}=\frac{1}{32}$
32=x⁵
5th root both sides
2=x
x=2